Circuit Wiring

This inverter circuit works with a transistor and transformer and other components to increase the voltage becomes high. Input supply voltage ranging from 3V to 6V DC, later it was raised to high voltage AC. However, in this inverter circuit output current is very small, probably under 0.1A even smaller. However, its use you can apply it on a fluorescent lamp 10W maximum power only, and that too takes time to switch on fluorescent lamps.

Part List
R1 = 4K7
R2 = 2K2
R3 = 330K
C1 = 100nF
C2 = 100nF 275V
C3 = 0.22uF 275V
Q1 = D506
L1 = 100 times winding, with 0.8mm diameter copper wire
L2 = 50 times winding, with 0.8mm diameter copper wire
L3 = 5000 times winding, with 0.4mm diameter copper wire

This inverter circuit can provide up to 800mA of 12V power from a 6V supply. For example, you could run 12V car accessories in a 6V (British?) car. The circuit is simple, about 75% efficient and quite useful. By changing just a few components, you can also modify it for different voltages.









Part List:

R1, R4 2.2K 1/4W Resistor

R2, R3 4.7K 1/4W Resistor

R5 1K 1/4W Resistor

R6 1.5K 1/4W Resistor

R7 33K 1/4W Resistor

R8 10K 1/4W Resistor

C1,C2 0.1uF Ceramic Disc Capacitor

C3 470uF 25V Electrolytic Capcitor

D1 1N914 Diode

D2 1N4004 Diode

D3 12V 400mW Zener Diode

Q1, Q2, Q4 BC547 NPN Transistor

Q3 BD679 NPN Transistor

L1 See Notes

MISC Heatsink For Q3, Binding Posts (For Input/Output), Wire, Board